0=3w^2-4w-55

Solution for 0=3w^2-4w-55 equation:

0=3w^2-4w-55

We move all terms to the left:

0-(3w^2-4w-55)=0

We add all the numbers together, and all the variables

-(3w^2-4w-55)=0

We get rid of parentheses

-3w^2+4w+55=0

a = -3; b = 4; c = +55;
Δ = b2-4ac
Δ = 42-4·(-3)·55
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-26}{2*-3}=\frac{-30}{-6}
=+5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+26}{2*-3}=\frac{22}{-6}
=-3+2/3
$